6u^2+8u+1=0

Solution for 6u^2+8u+1=0 equation:

6u^2+8u+1=0

a = 6; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·6·1
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{10}}{2*6}=\frac{-8-2\sqrt{10}}{12}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{10}}{2*6}=\frac{-8+2\sqrt{10}}{12}
$